Please, give me some minutes to take over your question
Real roots
y = -x^2 - 4x + 3
0 = x^2 + 4 -3
Using the quadratic formula
a= 1
b= 4
c= -3
[tex]x=\text{ }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex][tex]x=\text{ }\frac{-4\pm\sqrt[]{4^2-4\cdot1\cdot(-3)}}{2\cdot1}=\text{ }\frac{-4\pm\sqrt[]{16+12}}{2}=\text{ }\frac{-4\pm\sqrt[]{28}}{2}=\text{ }\frac{-4\pm\sqrt[]{7\cdot4}}{2}=\text{ }\frac{-4\pm2\sqrt[]{7}}{2}=\text{ }-2\pm\sqrt[]{7}[/tex]x1= -2 + √7
x2= -2 - √7
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Answer
x1= -2 + √7
x2= -2 - √7
