Respuesta :
Answer
C. 36.02
Explanation
Given:
Moles of hydrogen that reacts = 2 mol
Moles of oxygen that reacts = 1 mol
What to find:
The mass of water formed when the moles of hydrogen and oxygen above react.
Solution:
The first step is to write a balanced chemical equation for the reaction to know the mole ratio of H to O
[tex]2H_2+O_2\rightarrow2H_2O[/tex]The mole ratio of hydrogen to water in the balanced equation is 2:2
The next step is to calculate the mole of water produced from the given moles of H and O using the mole ratio.
[tex]\begin{gathered} 2mol\text{ }H_2=2mol\text{ }H_2O \\ \\ 2mol\text{ }H_2=x \\ \\ x=\frac{2mol\text{ }H_2}{2mol\text{ }H_2}\times2mol\text{ }H_2O \\ \\ x=2mol\text{ }H_2O \end{gathered}[/tex]The final step is to convert the 2 moles of water produced to mass in grams using the molar mass of water and mole formula.
The molar mass of water = 18.01g/mol
[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Mass=Moles\times Molar\text{ }mass \\ \\ Mass=2mol\times18.01g\text{/}mol \\ \\ Mass=36.02\text{ }g \end{gathered}[/tex]Hence, the mass of water formed is 36.02 g.
The answer is C. 36.02
