Respuesta :

We need to solve for y.

Let's expand the right hand side using the distributive property shown below:

[tex]a(b+c)=ab+ac[/tex]

Thus, the equation becomes:

[tex]\begin{gathered} 27=3(y+4) \\ 27=3y+12 \end{gathered}[/tex]

Now we take variables to one side and numbers to another and solve for y:

[tex]\begin{gathered} 27=3y+12 \\ 27-12=3y \\ 15=3y \\ y=\frac{15}{3} \\ y=5 \end{gathered}[/tex]

The solution is:

[tex]y=5[/tex]

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