Respuesta :

1) Given that for this Sequence we have an explicit formula:

[tex]a_n=3(-2)^{n-1}[/tex]

2) Since a recursive formula, always recur to the previous term let's find the 1st term:

[tex]\begin{gathered} a_n=3(-2)^{n-1} \\ a_1=3(-2)^0 \\ a_1=3 \end{gathered}[/tex]

Now the second term:

[tex]\begin{gathered} a_2=3(-2)^{2-1} \\ a_2=-6 \\ \end{gathered}[/tex]

Comparing them we can write the Recursive one:

[tex]\begin{gathered} a_n=-2a_{n-1\text{ }} \\ -6=-2(3) \\ -6\text{ = -6 true} \end{gathered}[/tex]

3) Then the answers are:

[tex]\begin{gathered} a_1=3 \\ a_n=-2a_{n-1\text{ }} \end{gathered}[/tex]

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