SOLUTION
We want to solve
[tex](x-5)^{2}=100[/tex]This becomes
[tex]\begin{gathered} (x-5)^{2}=100 \\ \text{squaroot both sides } \\ \sqrt[]{(x-5)^{2}}=\sqrt[]{100} \\ \text{Square cancels square root} \\ x-5=\sqrt[]{100} \\ i\text{ntroduce }\pm\text{ to the square root } \\ x-5=\pm\text{ }\sqrt[]{100} \\ \end{gathered}[/tex]So, we have
[tex]\begin{gathered} x-5=\pm\text{ }\sqrt[]{100} \\ x-5=\pm10 \\ x=5\pm10 \\ \text{either } \\ x=5+10=15 \\ Or \\ x=5-10=-5 \\ x=(-5,15) \end{gathered}[/tex]Option C is correct