Respuesta :

The equation is given to be:

[tex]3x^2-12x=9[/tex]

Divide each term by 3:

[tex]\begin{gathered} \frac{3x^2}{3}-\frac{12x}{3}=\frac{9}{3} \\ x^2-4x=3 \end{gathered}[/tex]

Add the square of half the coefficient of x to both sides of the equation:

[tex]\begin{gathered} Coefficient=-4 \\ Half=-\frac{4}{2}=-2 \\ Square=(-2)^2 \\ \therefore \\ x^2-4x+(-2)^2=3+(-2)^2 \\ x^2-4x+(-2)^2=7 \end{gathered}[/tex]

Complete the square:

[tex](x-2)^2=7[/tex]

The correct option is OPTION C.

ACCESS MORE
EDU ACCESS
Universidad de Mexico