Answer:
[tex]\begin{gathered} AB=17.48 \\ CB=19.064 \end{gathered}[/tex]
Explanation: We are provided one known side and angle and two unknown sides that we need to find. It can be done by using trignomatric ratios as follows:
[tex]\begin{gathered} AB=\text{?} \\ CB=\text{?} \\ AC=11 \\ \theta=39^{\circ} \\ \therefore\rightarrow \\ \sin (\theta)=\frac{Opposite\text{ }}{\text{Hypotenuse}}=\rightarrow\sin (39)=0.629=\frac{11}{AB} \\ \therefore\rightarrow \\ AB=\frac{11}{0.629}=17.48 \end{gathered}[/tex]
Similarly, CB side can be found as follows:
[tex]\begin{gathered} \tan (\theta)=\frac{Opposite}{\text{Adjacent}}\rightarrow\tan (39)=0.577=\frac{11}{CB} \\ \therefore\rightarrow \\ CB=\frac{11}{0.577}=19.064 \\ CB=19.064 \end{gathered}[/tex]
We have found missing sides which are AB and CB
