Question

It take you 11.3 minutes to walk an average velocity of 1.2 m/s to the north from the bus stop to the museum entrance what is your displacement

Answer 1

ANSWER

813.6 m

EXPLANATION

The average velocity is:

$v_{\text{avg}}=\frac{\Delta x}{\Delta t}$

Where Δx is the displacement.

In this problem we have vavg = 1.2 m/s and time 11.3min. First we have to convert the time from minutes to seconds, for the units to be consistent with the velocity's units:

$\begin{gathered} 1\min =60s \\ \Delta t=11.3\min \cdot\frac{60s}{1\min }=678s \end{gathered}$

Now, solving the equation above for Δx :

$\Delta x=v_{\text{avg}}\cdot\Delta t$

And replacing the values:

$\Delta x=1.2\frac{m}{s}\cdot678s=813.6m$

We found that the displacement is 813.6 meters