Question

Given that the zeros of a quadratic function are -4 and 6, what is the standard form of the quadratic function?

Answer 1

The factored form of a quadratic equation is

$\begin{gathered} f(x)=a(x-c_1)(x-c_2) \\ a\rightarrow\text{ constant} \\ c_1,c_2\rightarrow\text{ roots} \end{gathered}$

Therefore, in our case,

$\Rightarrow f(x)=(x+4)(x-6)$

Notice that no information about constant a is provided by the question,

$\Rightarrow f(x)=(x+4)(x-6)=x^2-2x-24$

The standard form of the quadratic function is x^2-2x-24