Question

2Drag each set of coordinates to the correct location on the table.Calculate the distance between the pairs of coordinates, and classify them according to the distance between them.(3, 4) and (2, 1)(3, 7) and (5,2)(5,-2) and (3, 3)(-2, 3) and (1, 2)(-4,-2) and (-3, 1)(4, -1) and (-1,1)TO units29 unitsResetNext

Answer 1

Step 1

State the distance between points formula

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step 2

Find the distance between the points

$\begin{gathered} D=\sqrt{(2-3)^2+(1-4)^2}=\sqrt{10}\text{ units} \\ (3.4)\text{ and \lparen2,1\rparen =}\sqrt{10}\text{ units} \end{gathered}$$\begin{gathered} D=\sqrt{(5-3)^2+(2-7)^2}=\sqrt{29\text{ }}units \\ (3,7)\text{ and \lparen5,2\rparen = }\sqrt{29\text{ }}\text{ units} \end{gathered}$$\begin{gathered} D=\sqrt{(3-5)^2+(3+2)^2}=\sqrt{29}\text{ units} \\ (5,-2)\text{ and \lparen3,3\rparen =}\sqrt{29}\text{ units} \end{gathered}$$\begin{gathered} D=\sqrt{(1-(-2))^2+(2-3)^2}=\sqrt{10\text{ }}units \\ (-2,3)\text{ and \lparen1,2\rparen=}\sqrt{10}\text{ units} \end{gathered}$$\begin{gathered} D=\sqrt{(-3-(-4))^2+(1-(-2))^2}=\sqrt{10}units \\ (-4,-2)\text{ and \lparen-3,-1\rparen=}\sqrt{10}units \\ \end{gathered}$$\begin{gathered} D=\sqrt{(-1-4)^2+(1-(-1)^2}=\sqrt{29}\text{ units} \\ (4,-1)\text{ and \lparen-1,1\rparen=}\sqrt{29}\text{ units} \end{gathered}$