Question

Find the x - and y - intercepts of the line. 4x + 3y = 12Y intercept: ( , )X intercept: ( , )

Answer 1

Y intercept: ( 0,4)

X intercept: (3 ,0)

1) Let's at first find the y-intercept. Then we need to plug into that x=0. Like this:

$\begin{gathered} 4x+3y=12 \\ 4(0)+3y=12 \\ 3y=12 \\ \frac{3y}{3}=\frac{12}{3} \\ y=4 \end{gathered}$

So the y-intercept is located at (0,4)

2) Now, similarly we can proceed with the same process, this time to find out the x-intercept. Plugging into the equation y=0

$\begin{gathered} 4x+3y=12 \\ 4x+3(0)=12 \\ 4x=12 \\ \frac{4x}{4}=\frac{12}{4} \\ x=3 \end{gathered}$

So we can write out the X intercept as (3,0)

3) Hence, the answers are:

Y intercept: ( 0,4 )

X intercept: (3 ,0 )