Question

Find the perimeter and area of arectangle with a width of 2 feet and alength 3 times as long.P=A=

Answer 1

We have that a rectangle has two pairs of congruent sides. We can find the perimeter as follows:

$P=2\cdot w+2\cdot l\Rightarrow P=2\cdot2ft+2\cdot3ft=4ft+6ft=10ft$

Therefore, the perimeter is equal to 10ft.

And the area is given by the product of the measure of the width and length:

$A_{\text{rectangle}}=w\cdot l=2ft\cdot3ft\Rightarrow A_{rec\tan gle}=6ft^2$

Therefore, the area of this rectangle is equal to 6 sq. feet.

In summary, we have:

• P = 10ft

,

• A = 6 ft^2