[tex]\begin{gathered} \text{If x are the number os SUVS and y the number of sedans, then} \\ 6x=2y \\ x=\frac{2}{6}y \\ x=\frac{1}{3}y \\ \\ \\ x+y=48 \\ \frac{1}{3}y+y=48 \\ \frac{4}{3}y=48 \\ \\ y=48\cdot\frac{3}{4} \\ y=36 \\ \\ \\ x+36=48 \\ x=48-36 \\ x=12 \\ \\ \text{ there are 12 SUVs and 36 sedans} \end{gathered}[/tex]