The given equation is:
[tex]|4c-10|=50[/tex]Recall that:
[tex]|x|=\begin{cases}{-x\text{ for }x\lt0} \\ {} \\ {x}\text{ for }x\geq0\end{cases}[/tex]Suppose (4c - 10) < 0, it follows that:
[tex]\begin{gathered} -(4c-10)=50 \\ 4c-10=-50 \\ 4c=-50+10 \\ 4c=-40 \\ c=-\frac{40}{4} \\ c=-10 \end{gathered}[/tex]Suppose (4c - 10) ≥ 0, it follows that:
[tex]\begin{gathered} (4c-10)=50 \\ 4c-10=50 \\ 4c=50+10 \\ 4c=60 \\ c=\frac{60}{4} \\ c=15 \end{gathered}[/tex]Therefore, the solution is:
c = -10 and c =15
.