the expression is
f(b) = 3b²- 5b + 2
[tex]\begin{gathered} f\mleft(b\mright)=3b^{2}-5b+2 \\ f\mleft(b\mright)=3b^{2}-3b-2b+2 \end{gathered}[/tex][tex]\begin{gathered} =3b(b-1)-2(b-1) \\ =(b-1)(3b-2) \end{gathered}[/tex]so the factors are (b - 1) and (3b - 2).
