Answer
Explanation
Given
[tex]f\mleft(x\mright)=-x^3+4x-2[/tex]Thus, to find the slope of the tangent line, we have to find the derivative:
[tex]f^{\prime}(x)=-3x^{3-1}+4\cdot1\cdot x^{1-1}-0[/tex][tex]f^{\prime}(x)=-3x2+4x^0[/tex][tex]f^{\prime}(x)=-3x2+4x^0[/tex]