Remember, the expression that represents a line is:
[tex]y=mx+b[/tex]
where b, is the y-intercept and the x-intercept is when y=0
Isolating y:
[tex]\begin{gathered} 3y=6-2x \\ y=-\frac{2}{3}x+2 \end{gathered}[/tex]
The y-intercept is (0, 2)
The x-intercept is:
[tex]\begin{gathered} 0=-\frac{2}{3}x+2 \\ -2=-\frac{2}{3}x \\ \frac{2\cdot3}{2}=x \\ x=\frac{6}{2}=3 \end{gathered}[/tex]
X-INTERCEPT=(3, 0)
The student error was that he substite x=0 for the x-intercept and y=0 for the y-intercept.
