Question

Find an equation of a line through with m = −3.

Answer 1

$y=-3x+\frac{10}{9}$

Explanation:

Data:

. Slope : m = -3

. Points of the graph:

. . x1 = 1/3

. . y1 = 1/9

Equation form:

$y-y_1=m(x-x_1)$

Solution:

$\begin{gathered} y-\frac{1}{9}=-3(x-\frac{1}{3}) \\ y-\frac{1}{9}=-3x+\frac{3}{3} \\ y=-3x+\frac{3*3}{3*3}+\frac{1}{9} \\ y=-3x+\frac{9}{9}+\frac{1}{9} \\ y=-3x+\frac{10}{9} \end{gathered}$