Question

Solve the following polynomial equation by grouping and factoring. 16y3−25y=0

Answer 1

Answer:

$\begin{gathered} \text{ Solutions for the polynomial:} \\ y=-\frac{5}{4},\text{ 0, }\frac{5}{4} \end{gathered}$

Step-by-step explanation:

Use common factor to factor ''y'':

$y(16y^2-25)=0$

Now, factor by grouping the perfect binomial:

$\begin{gathered} y(4y+5)(4y-5)=0 \\ \text{ Solve each factor independently:} \\ y=0 \\ \\ 4y+5=0 \\ y=-\frac{5}{4} \\ \\ 4y-5=0 \\ y=\frac{5}{4} \end{gathered}$