Given:
Is it possible to draw a triangle with a 6 mm side an 8 mm side and a 90° angle between them?
The sides of 6 mm and 8 mm and 90° angle between them, so, the sides will be the legs of a right-angle triangle
the hypotenuse of the triangle will be calculated using the Pythagorean theorem as follows:
[tex]h=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10[/tex]So, the answer will be Yes, it is possible.