Respuesta :

EXPLANATION:

We are given the absolute value functions below;

[tex]\begin{gathered} y=3|x| \\ y=-\frac{3}{4}|x| \\ y=-\frac{1}{2}|x| \\ y=-1|x| \end{gathered}[/tex]

Note that for this function, we have a v-shaped graph, since the values of the output is always positive (absolute value) and the vertex is at (0, 0). Also, if the value of a in the function;

[tex]y=a|x|[/tex]

is positive, the graph opens upwards, and if the value of a is negative;

[tex]y=-a|x|[/tex]

then it opens downwards.

Therefore,

ANSWER;

[tex]\begin{gathered} y=3|x|\text{ Opens upwards} \\ y=-\frac{3}{4}|x|\text{ Opens downwards} \\ y=-\frac{1}{2}|x|\text{ Opens downwards} \\ y=-1|x|\text{ Opens downwards} \end{gathered}[/tex][tex]\begin{gathered} The\text{ equation with the narrowest graph;} \\ y=3|x| \end{gathered}[/tex][tex]\begin{gathered} The\text{ equation with the widest graph;} \\ y=-\frac{1}{2}|x| \end{gathered}[/tex]

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