A ball is dropped from a height of 1600 meters. Each time the ban bouces, it reaches 3/4 of its original height. a) What are the first three terms of this sequence? b) Write an equation to represent this Sequence. c) Find the height of the ball after 4 bounces.

Respuesta :

We know that

• The ball is dropped from 1600 meters high.

,

• Each time it bounces 3/4 of its original height.

This situation creates a geometric sequence where the reason is 3/4. To find the first three terms of this sequence, we just have to multiply each term with 3/4. We know that the first term is 1600.

[tex]1600\cdot\frac{3}{4}=\frac{4800}{4}=1200[/tex]

The second term is 1200 meters.

[tex]1200\cdot\frac{3}{4}=\frac{3600}{4}=900[/tex]

The third term is 900.

To find an equation, we have to use the geometric sequence formula-

[tex]a_n=a_1\cdot r^{n-1}[/tex]

Replacing the information we have the equation that represents the situation of this problem.

[tex]a_n=1600\cdot(\frac{3}{4})^{n-1}[/tex]

At last, the height after 4 bounces is

[tex]900\cdot\frac{3}{4}=\frac{2700}{4}=675[/tex]

The height of the third bounce is 675 meters.

[tex]675\cdot\frac{3}{4}=\frac{2025}{4}=506.25[/tex]

Therefore, the height of the ball after 4 bounces is 506.25 meters.

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