Question

Evaluate the expression how do you get to (2^-1 x 3^0)^3 times (2^0 x 5^3) ^5

Answer 1

we have the expression

$(2^{-1}\cdot3^0)^{-3}\cdot(2^0\cdot5^3)^5$

Remember that

$\begin{gathered} 2^{-1}=\frac{1}{2} \\ 3^0=1 \\ 2^0=1 \\ 5^3=125 \end{gathered}$

substitute in the original expression

$\begin{gathered} (\frac{1}{2}\cdot1)^{-3}\cdot(1\cdot125)^5 \\ (\frac{1}{2}\cdot)^{-3}\cdot(125)^5 \end{gathered}$$\begin{gathered} (\frac{1}{2})^{-3}=2^3=8 \\ \end{gathered}$

substitute

$\begin{gathered} 8\cdot(125)^5 \\ 8\cdot30,517,578,125 \\ 244,140,625,000 \end{gathered}$

therefore

The answer is

244,140,625,000