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Answer

T' = (5, -1)

I' = (5, -3)

E' = (1, -1)

Explanation

Given the below triangle

T = ( -5, -1)

I = (-5, -3)

E = (-1, -1)

When reflected over y -axis, the x - cordinate is negated while the y - coordinate remains unchanged

Mathematically,

(x , y ) ------------------------ (-x , y)

T = ( -5, 1)

T' = [-(-5) , -1)]

T' = (5, -1)

I = (-5, -3)

I' = [-(-5) , -3)

I' = (5, -3)

E = (-1, -1)

E' = [-(-1), -1)]

E' = (1, -1)

Therefore, the reflected triangle over y - axis has the following points

T' = (5, -1)

I' = (5, -3)

E' = (1, -1)

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