Question

I am not understanding this question can you help me solve this? Please I desperately need your help

Answer 1

Given:

$\[g\left(x\right)=\left\{\begin{matrix}\sqrt[3]{x+5} \\ -{{x}^2}+11\end{matrix}\text{ }\begin{matrix}x\le-4 \\ x>-4\end{matrix}\right.\]$

To find:

The value of:

$g(-4)$

Explanation:

For x = -4, we can consider the below function,

$g(x)=\sqrt[3]{x+5}$

Substituting the value x = -4,

$\begin{gathered} g(-4)=\sqrt[3]{-4+5} \\ =\sqrt[3]{1} \\ =1 \end{gathered}$

Final answer:

Hence, the required solution is:

$(A)\text{ 1}$