Given:
Number of squares in figure 1 = 5
Number of squares in figure 2 = 8
Number of squares in figure 3 = 11
Let's find the number of squares in figure 10 if the pattern continues.
To solve this, let's apply the arithmetic progression formula:
a(n) = a1 + (n - 1)d
Where:
a1 = first term(squares in figure 1) = 5
n = number of terms = 10
d is the common difference.
To find the common difference, we have:
d = a2 - a1 = 8 - 5 = 3
Thus, the common difference is 3.
To find the number of squares in figure 10 (a10), we have:
a(n) = a1 + (n - 1)d
a(10) = 5 + (10 - 1)3
a(10) = 5 + (9)3
a(10) = 5 + 27
a(10) = 32
Therefore, the number of squares in figure 10 will be 32 squares .
ANSWER:
E. 32
