Question

The pyramid below has a square base with sides of 3 feet and congruent triangular sides with a height of 4 feet what is the total surface of the pyramid?

Answer 1

$\begin{gathered} \text{ the total surface is } \\ A_{\text{total}}=A_{\text{base}}+4A_{\text{triangle}} \\ \\ A_{\text{total}}=3^2+4(\frac{1}{2}4\cdot3) \\ A_{\text{total}}=9+4\times6 \\ \\ A_{\text{total}}\text{ = }9+24 \\ \\ A_{\text{total}}=33 \\ \\ \\ \text{ The total surface area is 33 square feet} \end{gathered}$