What is the area of parallelogram QRST? 400 in^2360 in^2 180 in^2210 in^2

Hello!
First, let's write some important information below to help us to solve this exercise:
• QR = 20in = TS
,• SR = 20in = TQ (base)(ba((bT
,• TU = 18in (height) (
To calculate the area of a parallelogram, we must use the formula below:
[tex]\begin{gathered} \mathrm{Area=base}\times\mathrm{height} \\ \mathrm{Area=}20\times18 \\ \mathrm{Area=}360\mathrm{in^2} \end{gathered}[/tex]:
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