Respuesta :

Hello!

First, let's write some important information below to help us to solve this exercise:

• QR = 20in = TS

,

• SR = 20in = TQ (base)(ba((bT

,

• TU = 18in (height) (

To calculate the area of a parallelogram, we must use the formula below:

[tex]\begin{gathered} \mathrm{Area=base}\times\mathrm{height} \\ \mathrm{Area=}20\times18 \\ \mathrm{Area=}360\mathrm{in^2} \end{gathered}[/tex]

:

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