Question

consider the recursive formula. The first term of the sequence is 10, what is the 3rd term?A. 1B. 4C. 6D. 8

Answer 1

Given the recursive formula:

$a_n=\frac{2+a_{n-1}}{2}$

and that the first term (that is a1=10) we have:

$\begin{gathered} a_2=\frac{2+10}{2}=\frac{12}{2}=6 \\ a_3=\frac{2+6}{2}=\frac{8}{2}=4_{} \end{gathered}$

Therefore the third term is 4