Answer:
f(3) = 8
Explanation:
The function we have is
[tex]f(x)=x^3-3x^2+5x-7[/tex]
To find f(3), we evaluate the above function at x = 3. This gives
[tex]f(3)=3^3-3*3^2+5*3-7[/tex]
which simplifies to give
[tex]f(3)=27-27+15-7[/tex][tex]\Rightarrow\boxed{f(3)=8.}[/tex]
To fill the table given, we evaluate the function at various values of x and record our output values.
Using the same approach as above, we find that
f(-2) = -37
f(-1) = -16
f(0) = -7
f(1) = -4
f(2) = -1
which we use to fill in the table.
