First, we need to find the z-score value for the given IQs. For IQ 70, we have
[tex]\begin{gathered} z=\frac{X-\mu}{\sigma} \\ z=\frac{70-100}{15} \end{gathered}[/tex]then,
[tex]z=\frac{-30}{15}=-2[/tex]Now, for IQ 130, we have
[tex]\begin{gathered} z=\frac{X-\mu}{\sigma} \\ z=\frac{130-100}{15} \\ z=\frac{30}{15} \\ z=2 \end{gathered}[/tex]This means that the given IQs falls with in 2 standard deviations. Therefore the answer is 95%
[tex]\mu-2\sigma\text{ and }\mu+2\sigma[/tex]