SOLUTION:
Case: Roots and Exponents
Method:
Simplifying
[tex]\begin{gathered} \sqrt[3]{320}\times\sqrt[3]{1080} \\ \sqrt[3]{64\times5}\times\sqrt[3]{216\times5} \\ \sqrt[3]{64}\times\sqrt[3]{5}\times\sqrt[3]{216}\times\sqrt[3]{5} \\ 4\times\sqrt[3]{5}\times6\times\sqrt[3]{5} \\ 4\times6\times\sqrt[3]{5}\times\sqrt[3]{5} \\ 24\sqrt[3]{25} \end{gathered}[/tex]
Final answer:
[tex]24\sqrt[3]{25}[/tex]
