Answer:
A'' = (1, -1)
V'' = (-3, -3)
F'' = (-6, -3)
C'' = (-2, 2)
Explanations:
Given the coordinate of the quadrilateral AVFC as shown:
A = (-1, 1)
V = (3, 3)
F = (6, 3)
C =(2, -2)
The rule for the 180° clockwise rotation about the origin is given as;
[tex](x,y)\rightarrow(-x,-y)[/tex]
This shows that the coordinates were negated but their original position must be retained.
For the coordinate points of the quadrilateral AVFC, the 180° clockwise rotation about the origin will be given as;
[tex]\begin{gathered} A(-1,1)\rightarrow A\text{''(-(-1),-1)}=A^{\doubleprime}(1,-1) \\ V(3,3)\rightarrow V\text{''(-3,-3)}=V^{\doubleprime}(-3,-3) \\ F(6,3)\rightarrow F\text{''(-6,-3)}=F^{\doubleprime}(-6,-3) \\ C(2,-2)\rightarrow C\text{''(-2,-(-2)}=C^{\doubleprime}(-2,2) \end{gathered}[/tex]
