The formula used here:
Enthalpy change = moles x molar enthalpy of vaporization
We already have 50.0 g of water. We should convert it to moles using the molar mass of water.
*Moles = mass/molar mass
The molar mass of water = 18.0 g/mol => 50.0 g/18.0 g/mol = 2.78 moles
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The molar Enthalpy of vaporization = 44.0 kJ/mol
Now, Enthalpy change = 2.78 moles x 44.0 kJ/mol = 122 kJ
Answer: enthalpy change = 122 kJ