We have to calculate the area of a triangle with height h = √343 cm and base b = √28 cm.
We can use the formula:
[tex]\begin{gathered} A=\frac{1}{2}bh \\ A=\frac{1}{2}\sqrt[]{28}\cdot\sqrt[]{343} \\ A=\frac{1}{2}\sqrt[]{28\cdot343} \\ A=\frac{1}{2}\sqrt[]{9604} \\ A=\frac{1}{2}\sqrt[]{4\cdot49\cdot49} \\ A=\frac{1}{2}\sqrt[]{4}\cdot\sqrt[]{49}^2 \\ A=\frac{1}{2}\cdot2\cdot49 \\ A=49\operatorname{cm}^2 \end{gathered}[/tex]Answer: the are of the triangle is 49 cm²
