Question

3. A parallel-plate capacitor has a charge of 8.6 uc when charged by a potential difference of 3.5 V. What is its capacitance? * (3 Points) 25 x 10-60

Answer 1

The charge in a capacitor is given by:

$Q=CV$

Plugging the values of the charge anf the potential differnce and solving for the capacitance we have:

$\begin{gathered} 8.6\times10^{-6}=3.5C \\ C=\frac{8.6\times10^{-6}}{3.5} \\ C=2.5\times10^{-6} \end{gathered}$

Therefore the capacitance is:

$2.5\times10^{-6}\text{ F}$