Answer:
7) -6 and 1
Explanations:
The standard quadratic equation is expressed as:
[tex]f(x)=ax^2+bx+c[/tex]
The expression in factored form is given as:
[tex]f(x)=(x-a)(x-b)[/tex]
where a and b are zeros of the quadratic equation:
From the graph, the zeros of the function are the point where the curve cuts the x-axis. The zeros of the equation are -6 and 1
Substitute the given zeros into the factored form;
[tex]\begin{gathered} f(x)=(x-(-6))(x-1) \\ f(x)=(x+6)(x-1) \\ f(x)=x^2-x+6x-6 \\ f(x)=x^2+5x-6 \end{gathered}[/tex]
Hence the solution of the quadratic equation depicted in the graph are -6 and 1
