Question

11. If ABDC is an isosceles trapezoid,what is the value of x?C82⁰A8(5×-40)D12

Answer 1

Since ABCD is an isosceles trapezoid we have that:

$\angle C=\angle D$

So, substitute each angle:

$82=5x-40$

And solve for x:

$\begin{gathered} 82+40=5x-40+40 \\ 122=5x \\ \frac{122}{5}=\frac{5x}{5} \\ x=24.4 \end{gathered}$

Answer: x = 24.4