in a standard deck of 52 playing cards, there are 4 queen cards. use this information to answer the following. (1 point each) a. what is the probability of drawing two queens in a row (a queen and a queen) without replacement? b. what is the probability of drawing two queens in a row (a queen and a queen) with replacement? c. are your chances of drawing two queens in a row better with or without replacement?

Respuesta :

a.)  Probability of drawing two queens in a row (a queen and a queen) without replacement  = 0.00452

b.) Probability of drawing two queens in a row (a queen and a queen) with replacement = 0.00592

c.) Chances of drawing two queens in a row better with replacement

Define Probability

Simply put, probability is the likelihood that something will occur.

When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes.Statistics is the study of events that follow a probability distribution.

Given,

Total possible outcome = 52

There are 4 queens in a deck of 52 cards

a.)

Find, Probability of drawing two queens in a row (a queen and a queen) without replacement.

let, P stands for probability.

P (of drawing 1st queen) = 4 / 52

P(of drawing 2nd queen) = 3 / 51

P(drawing 2 queens in a row without replacement) =  4 / 52  *  3 / 51

                                                                                     = 0.000452

Hence, Probability of drawing two queens in a row (a queen and a queen) without replacement  = 0.00452

b.)

Find, Probability of drawing two queens in a row (a queen and a queen) with replacement

P (of drawing 1st queen) = 4 / 52

P(of drawing 2nd queen) = 4 / 52

P(drawing 2 queens in a row with replacement) = 4 / 52 * 4 / 52

                                                                               = 0.00592

Probability of drawing two queens in a row (a queen and a queen) with replacement = 0.00592

c.) Hence, the probability of with replacement is more so that's why

chances of drawing two queens in a row better with replacement

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