Given:
The voltage of the battery, V=10.0 V
The resistor of the resistance, R=2.00 Ω
To find:
The current coming out of the battery.
Explanation:
From Ohm's law, the voltage across a circuit is directly proportional to the current through the circuit.
Thus, the voltage of the battery is given by,
[tex]V=IR[/tex]Where I is the current coming out of the battery.
On substituting the known values,
[tex]\begin{gathered} 10.0=I\times2.00 \\ \Rightarrow I=\frac{10.0}{2.00} \\ =5.00\text{ A} \end{gathered}[/tex]Final answer:
The current coming out of the battery is 5.00 A.
Thus the correct answer is option E.