Question

Need help finding the answer to see where i went wrong(15)

Answer 1

Given that a line has its x-intercept as -8 and its y-intercept as 5, we can determine the slope of a line perpendicular to this line below.

Explanation

We can derive two points that the given line passes through using the x and y-intercept. This can be expressed as;

$\begin{gathered} x_1,y_1=(-8,0) \\ x_2,y_2=(0,5) \end{gathered}$

Therefore using the slope formula we would have;

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-0}{0-(-8)}=\frac{5}{8}$

For two lines to be perpendicular, their slope can be expressed as;

$\begin{gathered} m_1m_2=-1 \\ \therefore taking\text{ the slope of the given line as }m_1 \\ \frac{5}{8}\times m_2=-1 \\ \frac{5m_2}{8}=-1 \\ 5m_2=-8 \\ m_2=-\frac{8}{5} \end{gathered}$

Answer:

$m_{2}=-\frac{8}{5}$