Given:
volume of the rock is
[tex]V=6.0\text{ cm}^3[/tex]The mass of the rock is
[tex]m=30.0\text{ g}[/tex]Required: Density of the rock is to be calculated
Explanation:
To calculate the density of the rock we will use the formula that is given as
[tex]\rho=\frac{m}{V}[/tex]first, change the respective quantities in SI form
then volume of the rock is
[tex]\begin{gathered} V=6.0\text{ cm}^3 \\ V=6.0\text{ cm}^3\text{ }\times\frac{1\text{ m}^3}{10^6\text{ cm}^3} \\ V=6.0\times10^{-6}\text{ m}^3 \end{gathered}[/tex]Similarly for mass of the rock
then
[tex]\begin{gathered} m=30.0\text{ g}\times\frac{1\text{ kg}}{10^3\text{ g}} \\ m=30.0\times10^{-3}\text{ Kg} \end{gathered}[/tex]plugging all the values in the above relation, we get
[tex]\begin{gathered} \rho=\frac{m}{V} \\ \rho=\frac{30.0\times10^{-3}\text{ Kg}}{6.0\times10^{-6}\text{ m}^3} \\ \rho=500.0\text{ kg/m}^3 \end{gathered}[/tex]Thus, the density of the rock is
[tex]500.0\text{ kg/m}^3[/tex]
