If DE= 10 in and GH= 4in what is the length of the radius? Round to the nearest tenth

Solution
Using Pythagoras
[tex]\begin{gathered} GE^2=ME^2+GM^2 \\ ME=5 \\ GM=2 \\ GE^2=5^2+2^2 \\ GE^2=25+4 \\ GE^2=29 \\ Take\text{ the square root} \\ GE=\sqrt{29} \\ GE=5.3851 \end{gathered}[/tex]GE is the radius
Therefore, the final answer
Option A
[tex]5.4in[/tex]