[tex]\frac{\frac{1}{6}+\frac{-1}{3}}{\frac{3}{4}}[/tex]
First, we have to solve the addition, to add we need the bottom numbers of the fraction to be the same so:
Multiply the second fraction by 2 ( top and bottom number)
[tex]\frac{\frac{1}{6}-\frac{2}{6}}{\frac{3}{4}}[/tex][tex]\frac{-\frac{1}{6}}{\frac{3}{4}}[/tex]
Dividing by 3/4 is the same that multiply by 4/3 , so:
[tex]-\frac{1}{6}\times\frac{4}{3}=-\frac{4}{18}[/tex]
Simplify:
[tex]-\frac{2}{9}[/tex]
