To solve this problem we will use the formula for compound interest:
[tex]P_N=P_0\cdot\mleft(1+\frac{r}{k}\mright)^{N\cdot k}\text{.}[/tex]Where:
• P_N is the balance in the account after N years,
,• P_0 is the starting balance of the account (also called an initial deposit, or principal),
,• r is the annual interest rate in decimal form,
,• k is the number of compounding periods in one year.
In this problem, we have that:
• N = 6 (6 years),
,• P_N is the unknown,
,• P_0 = 500,
,• r = 4.5/100 = 0.045 (in decimals),
,• k = 4 (because the interest compounded quarterly).
Replacing these values in the formula above, we find the following equation for this scenario:
[tex]P_6=500\cdot(1+\frac{0.045}{4})^{6\cdot4}\cong653.9956[/tex]