Which is the first step?Evaluate the first equation for x = -5.O Evaluate the second equation for x = -1.O Evaluate the second equation for x = 5.O Evaluate the first equation for x = -1.

Which is the first stepEvaluate the first equation for x 5O Evaluate the second equation for x 1O Evaluate the second equation for x 5O Evaluate the first equat class=

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Explanation

A piecewise function formed by two equations with domains a≤x

In this case the two equations are:

[tex]\begin{gathered} f(x)=2x+3n \\ h(x)=2x^2-3x-9 \end{gathered}[/tex]

They are both polynomials so we know they are continuous in their respective domains. Then we just need to compare the values of f and h at x=-1 which is the value where their domains meet. Then the first step would be evaluating the first equation at x=-1:

[tex]f(-1)=2\cdot(-1)+3n=-2+3n[/tex]

Then we evaluate the second equation at x=-1:

[tex]\begin{gathered} h(-1)=2\cdot(-1)^2-3\cdot(-1)-9 \\ h(-1)=-4 \end{gathered}[/tex]

Then we have to look for the value of n that makes h(-1)=f(-1). Then we equalize these two results:

[tex]-2+3n=-4[/tex]

And we solve this equation for n. We can start by adding 2 to both sides:

[tex]\begin{gathered} -2+3n+2=-4+2 \\ 3n=-2 \end{gathered}[/tex]

And we divide both sides by 3:

[tex]\begin{gathered} \frac{3n}{3}=-\frac{2}{3} \\ n=-\frac{2}{3} \end{gathered}[/tex]Answer

The first step to find n is evaluating the first equation for x=-1. Then the answer is the fourth option.

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