Respuesta :

Answer:

x={0,1,6}

Given:

[tex]x^3+6x=7x^2[/tex]

Let us first arrange the equation and equate it to 0

[tex]\begin{gathered} x^3+6x=7x^2 \\ x^3-7x^2+6x=0 \end{gathered}[/tex]

Factor out x:

[tex]x(x^2-7x^{}+6)=0[/tex]

Then, factor out the quadratic equation inside the parenthesis using factoring:

[tex]\begin{gathered} x(x^2-7x^{}+6)=0 \\ x^2-7x^{}+6=(x-6)(x-1) \\ \rightarrow x(x-6)(x-1)=0 \end{gathered}[/tex]

Now, we will equate each factor to 0 to find the solution to the equation

[tex]\begin{gathered} x(x-6)(x-1)=0 \\ x=0 \\ ----------- \\ x-6=0 \\ x=6 \\ ----------- \\ x-1=0 \\ x=1 \end{gathered}[/tex]

Therefore, the solutions to the equation is x={0,1,6}

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