The sum of the inside angles of a triangle, always sum up to 180 degrees. Using this information, we can create the following equation for this problem:
[tex](3x-2)\text{ +(6}x\text{+11)+(5}x\text{ +3) = 180}[/tex]Adding up all terms with 'x' and adding the other together, we have the following equation:
[tex]\begin{gathered} (3x+6x+5x)+(11+3-2)=180_{} \\ 14x+12=180 \\ 14x=180-12=168 \end{gathered}[/tex]Solving this last equation for 'x', we have the following:
[tex]\begin{gathered} 14x=168 \\ x=\frac{168}{14}=12 \end{gathered}[/tex]Then, the final answer for the 'x' value is twelve!
