take the square root of both sides of the equation from part B ( nā2ācā2=0 ) and write the resulting equation. how can this equation be true, and what does this show about the relationship between the two triangles?


SOLUTION
From the question and the instructions given,
Since
[tex]\begin{gathered} n^2-c^2=0 \\ square\text{ rooting both sides } \\ \sqrt{n^2}-\sqrt{c^2}=\sqrt{0} \\ square\text{ cancels square root, we have} \\ n-c=0 \end{gathered}[/tex]Thus, the triangles have all sides congruent, since the triangles are congruent.
Hence, this means that triangle 1 is a right triangle.