Ok, so
Remember that:
For any quadratic equation of the form:
[tex]y=ax^2+bx+c[/tex]- If the leading coefficient is greater than zero, the parabola opens upward, and
- If the leading coefficient is less than zero, the parabola opens downward.
So, here we have the following functions:
[tex]v=\frac{1}{3}x^2-8x-13[/tex]The leading coefficient is greater than zero, so this parabola opens upward.
Option B:
[tex]\begin{gathered} v=-(3+x^2) \\ v=-x^2-3 \end{gathered}[/tex]The leading coefficient is less than zero, so this parabola opens downward.
Option C:
[tex]v=\frac{2}{3}x^2-13x+5[/tex]The leading coefficient is greater than zero, so this parabola opens upward.
Option D:
[tex]v=2x-x^2[/tex]The leading coefficient is less than zero, so this parabola opens downward.
Therefore, the correct options are B and D.