Respuesta :

Ok, so

Remember that:

For any quadratic equation of the form:

[tex]y=ax^2+bx+c[/tex]

- If the leading coefficient is greater than zero, the parabola opens upward, and

- If the leading coefficient is less than zero, the parabola opens downward.

So, here we have the following functions:

[tex]v=\frac{1}{3}x^2-8x-13[/tex]

The leading coefficient is greater than zero, so this parabola opens upward.

Option B:

[tex]\begin{gathered} v=-(3+x^2) \\ v=-x^2-3 \end{gathered}[/tex]

The leading coefficient is less than zero, so this parabola opens downward.

Option C:

[tex]v=\frac{2}{3}x^2-13x+5[/tex]

The leading coefficient is greater than zero, so this parabola opens upward.

Option D:

[tex]v=2x-x^2[/tex]

The leading coefficient is less than zero, so this parabola opens downward.

Therefore, the correct options are B and D.

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